2s^2-11s+6=0

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Solution for 2s^2-11s+6=0 equation: 



2s^2-11s+6=0

a = 2; b = -11; c = +6;
Δ = b2-4ac
Δ = -112-4·2·6
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{73}}{2*2}=\frac{11-\sqrt{73}}{4}
$


$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{73}}{2*2}=\frac{11+\sqrt{73}}{4}
$

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